WebJun 24, 2013 · You can use str.split () to convert the sentence to a list of words: a = 'the dogs barked'.split () This will create the list: ['the', 'dogs', 'barked'] You can then count the number of exact occurrences using list.count (): a.count ('dog') # 0 a.count ('dogs') # 1 If it needs to work with punctuation, you can use regular expressions. For example: WebJan 31, 2024 · long_string = "Extract the list of words with given length from a string using Python". length_required = 4. Tokenize the string into words. This can be done by …
Python - Combine all items in a list into a string - Stack Overflow
WebAug 5, 2024 · Use a dictionary that maps each letter to a list of words. This is some sample code: from collections import defaultdict letterWordsDict = defaultdict (lambda: []) # Let ls contain sub-lists of words. for subls in ls: for word in subls: letterWordsDict [word [0]].append (word) groupedWords = letterWordsDict.values () Share Follow WebSep 15, 2011 · Simple string operation: mywords = ("xxx", "yyy", "zzz") all (x in mystring for x in mywords) If word boundaries are relevant (i. e. you want to match zzz but not Ozzzy ): import re all (re.search (r"\b" + re.escape (word) + r"\b", mystring) for word in mywords) Share Improve this answer Follow edited Sep 15, 2011 at 11:54 screw sense
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WebDec 10, 2012 · In python the method sort () sorts all strings alphabetically so you can use that function. You can make a list of all your words and then : listName.sort () This would result a alphabetically sorted list. Share Improve this answer Follow answered Dec 10, 2012 at 21:34 Fyre 1,170 8 12 Add a comment 0 Just use the following: WebNov 5, 2024 · In this example, we will discuss how to find the string from a list in Python by using the count () method. The count () function is used to determine how many times a … WebThe simplest and most pythonic way, I believe, is to break the strings down into individual words and scan for a match: string = "My Name Is Josh" substring = "Name" for word in string.split (): if substring == word: print ("Match Found") For a bonus, here's a oneliner: any (substring == word for word in string.split ()) Share screw sems